MHB Find the integral of this function

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The integral of the function f(x,y) = 1/(x^2 + y^2 + 1)^(3/2) over the closed ball centered at point a with radius 2 is discussed. There is a clarification that the variable a should represent the center of the disk rather than the radius. The goal is to evaluate the integral as a approaches infinity, ultimately showing that the double integral equals 2π. The discussion emphasizes the importance of correctly interpreting the parameters in the integral setup. The conclusion reinforces the need for precision in mathematical notation and definitions.
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Find the integral of the function $f(x,y) = \frac{1}{(x^2 + y^2 + 1)^{\frac{3}{2}}} $
over the closed ball $\overline{B(a, 2)}$(i.e disk with radius 2 centered at point a). Letting $a \rightarrow \infty$, show that:

$\int_{-\infty}^{\infty} \int_{-\infty}^{\infty}f(x,y) dydx = 2\pi$
 
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kalvin said:
Find the integral of the function $f(x,y) = \frac{1}{(x^2 + y^2 + 1)^{\frac{3}{2}}} $
over the closed ball $\overline{B(a, 2)}$(i.e disk with radius 2 centered at point a). Letting $a \rightarrow \infty$, show that:

$\int_{-\infty}^{\infty} \int_{-\infty}^{\infty}f(x,y) dydx = 2\pi$
:confused: That wording cannot be correct: $a$ must surely be the radius of the disc, not its centre?
 
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