Find the Least Upper Bound for P(X>=5) with Chebychev Probability and E[e^X]=19

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SUMMARY

The discussion focuses on finding the least upper bound for the probability P(X ≥ 5) using Chebyshev's inequality in the context of a non-negative random variable X with the moment-generating function E[e^X] = 19. The participant initially applies Chebyshev's inequality incorrectly by substituting E(X) instead of correctly manipulating E[e^X]. The correct approach involves recognizing that if X ≥ 5, then e^X ≥ e^5, leading to the conclusion that P(e^X ≥ e^5) ≤ E[e^X]/e^5, which simplifies to P(X ≥ 5) ≤ 19/e^5.

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A non-negative random value X such that

E[e^X]=19
If p be the probability that the random value is at least 5 then what is the least upper bound you can give for the probability p with this information?

i think that i must use the type of chebychev like this

p(X>=5)<=(E(X)/5) but we have E(e^X) if i put e^X=Y then i will have this

p(e^X>=5)<=(E(Y)/5) and i am taking ln(log) and i have: p(X>=5)<=19/5 but the quiz says that 19/5 its not correct any ideas?
 
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If ##X\geq 5##, what bound can you put on ##e^X##?
 

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