- #1

- 2,546

- 340

- Homework Statement
- see attached

- Relevant Equations
- Geometry

Text question is here and solution;

My approach;

##BP ×AP= PT^2##

Let ##AP= x##

Therefore, ##(6+x)x=16##

##x^2+6x-16=0##

##x=2## or##x=-8##

##⇒x=2## positive value only.

I guess this may be the only approach. Cheers!

My approach;

##BP ×AP= PT^2##

Let ##AP= x##

Therefore, ##(6+x)x=16##

##x^2+6x-16=0##

##x=2## or##x=-8##

##⇒x=2## positive value only.

I guess this may be the only approach. Cheers!