Find the magnitude of the gravitational field

In summary, to find the magnitude of the gravitational field at a distance r from an infinitely long uniform thin rod with mass per unit length lambda, the equation dgx=-Gdm/r^2 can be used. Substituting in the given values and integrating, the final answer should be in terms of lambda, r, and G, with no mention of M, r1, or r2. More details are needed to determine any errors.
  • #1
matt_crouch
161
1

Homework Statement



Find the magnitude of the gravitational field a distance r from an infinitly long uniform thin rod whose mass per unit length is (lamda)

Homework Equations





The Attempt at a Solution



Need some clarification really
i know

dgx=-Gdm/r2

r=r2-r1

lamda=m/L

i substituded them in and intergrated

so to finally get

=-GM/r22-r12
 
Physics news on Phys.org
  • #2
You need to show the details of what you did. Otherwise it is hard to figure out what you did wrong. However, your final answer must be in terms of lambda r and G. There should be no M (the mass of the rod is infinite) or r1 and r2 (there is only one r, the distance of the point of interest to the rod).
 
  • #3



I would first clarify the units of the given mass per unit length (lambda) to ensure that the units are consistent with the gravitational constant G. Then, I would explain that the gravitational field is a vector quantity and its magnitude can be calculated using the equation:

g = -G * (lambda / r)

where G is the gravitational constant, lambda is the mass per unit length, and r is the distance from the rod. This equation can be derived by considering the gravitational force between a small section of the rod and a mass at distance r from it.

The integral approach taken in the attempt at a solution is also valid, as the gravitational field can be calculated by integrating the contributions from each small section of the rod. However, the limits of integration and the substitution of r2-r1 for r may need further clarification. Additionally, the negative sign in the equation should be taken into account as it indicates the direction of the gravitational field.
 

1. What is the definition of "magnitude of the gravitational field"?

The magnitude of the gravitational field is a measure of the strength of the gravitational force at a specific point in space. It is represented by the letter "g" and is measured in units of meters per second squared (m/s²).

2. How is the magnitude of the gravitational field calculated?

The magnitude of the gravitational field can be calculated using the formula g = G * m / r², where G is the universal gravitational constant, m is the mass of the object creating the gravitational field, and r is the distance from the object to the point where the field is being measured.

3. What factors affect the magnitude of the gravitational field?

The magnitude of the gravitational field is affected by two main factors: the mass of the object creating the field and the distance from that object. The greater the mass of the object, the stronger the gravitational field will be. Similarly, the closer an object is to the source of the field, the stronger the field will be.

4. How does the magnitude of the gravitational field vary on different planets or celestial bodies?

The magnitude of the gravitational field varies depending on the mass and size of the planet or celestial body. For example, the gravitational field on Earth is stronger than on the Moon because Earth has a larger mass and a larger radius. Similarly, the gravitational field on Jupiter is stronger than on Earth because Jupiter has a much larger mass.

5. What is the significance of finding the magnitude of the gravitational field?

Finding the magnitude of the gravitational field is important in understanding the behavior of objects under the influence of gravity. It allows us to calculate the force of gravity between objects and predict their motion. It also helps us understand the structure and formation of celestial bodies, such as planets and stars.

Similar threads

  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
972
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
3K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
965
Back
Top