MHB Find the mass and center of mass of the lamina

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The mass of the lamina occupying region D with the density function ρ(x, y) = 7xy² is calculated using the double integral formula, resulting in a mass of 7/3. To find the center of mass, the coordinates are determined using the integrals for \(\overline{x}\) and \(\overline{y}\), which depend on the mass. A user calculated the center of mass as (80/9, 0) but received feedback indicating this result is incorrect. Providing detailed calculations is essential for identifying errors and receiving accurate assistance.
carl123
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Find the mass and center of mass of the lamina that occupies the region D and has the given density function ρ.
D = {(x, y) | 0 ≤ x ≤ 1, −1 ≤ y ≤ 1}; ρ(x, y) = 7xy2

I got my mass to be 7/3 but I'm not sure how to go about finding the center of mass
 
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The mass of the lamina is given by the formula $$m=\iint_D \rho (x, y)dA$$ and the center of mass of the lamina is $(\overline{x}, \overline{y})$ where $$\overline{x}=\frac{1}{m}\iint_D x \rho (x, y)dA \ \ \text{ and } \ \ \overline{y}=\frac{1}{m} \iint_D y \rho (x, y)dA$$
 
mathmari said:
the center of mass of the lamina is $(\overline{x}, \overline{y})$ where $$\overline{x}=\frac{1}{m}\iint_D x \rho (x, y)dA \ \ \text{ and } \ \ \overline{y}=\frac{1}{m} \iint_D y \rho (x, y)dA$$

Thanks for your reply, I got (80/9 , 0) as my center of mass but it appears to be wrong, not sure why
 
carl123 said:
Thanks for your reply, I got (80/9 , 0) as my center of mass but it appears to be wrong, not sure why

If you show your working, then perhaps it can be found where you went wrong, and how to correct it. If you simply say, "I got such and such and it is wrong, but I don't know why," this doesn't give us anything with which we can help. :)
 

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