isukatphysics69
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The discussion revolves around finding the maximum compression of a spring in a system involving kinetic energy (KE), gravitational potential energy (GPE), and spring potential energy (SPE). Participants are analyzing energy conservation principles and the relationships between different forms of energy in the context of a mechanical system.
Some participants have offered guidance on correcting signs in equations and clarifying the treatment of energy types. There is ongoing exploration of different interpretations of the energy equations, with no explicit consensus reached on the correct approach.
Participants note confusion regarding the initial conditions of the system, the treatment of negative values in calculations, and the implications of energy types on the final results. There is also mention of homework constraints that may limit the exploration of certain methods.
What about GPE?isukatphysics69 said:Homework Statement
View attachment 225073
Homework Equations
ke = .5mv^2
The Attempt at a Solution
Ei= .5m1v21 + .5m2v22 + PEs(PEs initially 0)
Ef= .5m1v21 + .5m2v22 + PEs(PEs is now .5(16.2)(.2672)set them equal and then solve for velocity right? is this the right approach?
Why the sign change on the second term?isukatphysics69 said:ok i need help
initial energy is 0 for this system, final energy is
EFINAL = .5m1v2FINAL + .5m2v2FINAL +.5(16.2)(.2672)+((.481)(9.8)(-.267))
So
0 = .5m1v2FINAL - .5m2v2FINAL +.5(16.2)(.2672)+((.481)(9.8)(-.267))
solve for vFINAL
why is this not correct?
sorry that is not what i meant i meantharuspex said:Why the sign change on the second term?
Why? The KE and spring PE are both gains in energy. The only energy lost is the GPE.isukatphysics69 said:i meant to put negative spring potential energy
Your reasoning was correct. v2 should not have turned out negative.isukatphysics69 said:ok i just got the answer by doing something i was telling myself not to do
so it says speed. I was getting a negative value and i was going to square root it but knew i didn't want to square root a negative. since it says speed i decided to omit the negative and got the correct answer of 1.37m/s
isukatphysics69 said:0 = .5m1v2FINAL - .5m2v2FINAL - .5(16.2)(.2672)+((.481)(9.8)(.267))
and solving for v gave the correct answer