Spring Constant when compressed

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SUMMARY

The discussion centers on calculating the spring constant for a 6kg block sliding down a frictionless 1.0m ramp and compressing a spring by 45 cm. The gravitational potential energy (PEg) is calculated as 58.8 Joules using the formula PEg = mgh. The elastic potential energy (PEs) is represented by the equation PEs = 1/2kx^2. By applying the principle of energy conservation, the gravitational potential energy is equated to the elastic potential energy to determine the spring constant.

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  • Understanding of gravitational potential energy (PEg)
  • Familiarity with elastic potential energy (PEs)
  • Knowledge of energy conservation principles
  • Basic algebra for solving equations
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  • Learn how to derive the spring constant using different methods
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Homework Statement



A 6kg block is released from the top of a 1.0m ramp (frictionless) and slides into a horizontal spring, compressing it 45 cm. Determine the spring constant.



Homework Equations



PEg = mgh (6*9.8*1) = 58.8

PEs = 1/2kx^2 (1/2*k*.45^2)



The Attempt at a Solution



Do I set the two equations equal to each other and get 582.2 as the spring constant?
 
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Yeah that seems like the right approach to use: energy conservation. All of the gravitational PE that the object had at the top of the ramp is converted into KE by the time it reaches the bottom of the ramp, and then into elastic PE as it compresses the spring. So assuming no losses due to friction, you can equate the initial and final PE.
 

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