Find the nth term of 1/3+4/243+1/243+16/19,683?

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The discussion focuses on finding the nth term of the series 1/3 + 4/3^5 + 9/3^7 + 16/3^9. Participants suggest that the first term should be corrected to 1/3^3 instead of 1/3, leading to the conclusion that the nth term can be expressed as n^2/3^(2n+1). This adjustment clarifies the pattern in the series and resolves the confusion regarding the third term, which was identified as a potential typo.

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GiannaMe'arah
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by simplifying the denominator, 1/3 + 4/3^5 + 9/3^7 + 16/3^9

Cant find the nth term. i am assuming there is something wrong with the given. i suppose 1/3 should be 1/3^3. If so, then the nth term is n^2/3^(2n+1)

thanks.. :)
 
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In your title you wrote 1/3+4/243+1/243+16/19,683?

Was the third term a typo? If it's how you write it in your post, then yeah, I think the first should be 1/35 instead.
 

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