Find the particular solution of the second order differential equation

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Homework Help Overview

The discussion revolves around finding a particular solution to a second-order differential equation, specifically focusing on the method of solving simultaneous equations for coefficients in a trigonometric context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formulation of a particular solution in terms of sine and cosine functions, and the need to equate coefficients to solve for parameters. There is mention of using Laplace transforms as an alternative method, with some participants expressing a need to refresh their understanding of this approach.

Discussion Status

Several participants are actively engaging with the problem, exploring different methods and clarifying their understanding of the simultaneous equations involved. There is an acknowledgment of the complexity of the problem, with some guidance offered on how to approach the solution using trigonometric identities and Laplace transforms.

Contextual Notes

Participants note the importance of understanding both homogeneous and inhomogeneous approaches in solving ordinary differential equations. There are also references to constraints regarding the use of AI tools for assistance in technical discussions.

chwala
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Homework Statement
see attached
Relevant Equations
understanding of homogenous and inhomegenous approach in solving ode's
My interest is on the highlighted (In Red). Otherwise the other steps are clear.

1712993429550.png



1712993460897.png


We have on that part of the problem,

##(-p\sin t -q\cos t)-12(p\cos t -q \sin t)+36p\sin t +36q\cos t = 37 \sin t + 0 \cos t##

Ah I just realized we are solving a simultaneous equation for ##p## and ##q## !

My problem was on how to get,

##-q-12p+36q =0##

Clear now.

Cheers if there is another approach to the problem. Laplace? I may need to refresh on it.

I now have (using laplace);

##s^2 \bar y -12(s\bar y -1) +36 \bar y = \dfrac {37}{s^2+1}##

##\bar y = \dfrac{37}{(s^2+1)(s-6)^2} - \dfrac{12}{(s-6)^2}## will proceed later.
 
Last edited:
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chwala said:
Ah I just realized we are solving a simultaneous equation for p and q !
Hope you figured it out.
The idea is that a particular solution will be ##x_p = A\sin(t) + B\cos(t)##
When you substitute the above into x'' - 12x' + 36x you'll have some combination of sine and cosine terms that must be identically equal to ##37\sin(t)##. Since there is no cosine term, its coefficient must be zero. This will allow you to determine A and B.
 
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chwala said:
Homework Statement: see attached
Relevant Equations: understanding of homogenous and inhomegenous approach in solving ode's

My interest is on the highlighted (In Red). Otherwise the other steps are clear.

View attachment 343289


View attachment 343290

We have on that part of the problem,

##(-p\sin t -q\cos t)-12(p\cos t -q \sin t)+36p\sin t +36q\cos t = 37 \sin t + 0 \cos t##

Ah I just realized we are solving a simultaneous equation for ##p## and ##q## !

My problem was on how to get,

##-q-12p+36q =0##

Clear now.

Cheers if there is another approach to the problem. Laplace? I may need to refresh on it.

I now have (using laplace);

##s^2 \bar y -12(s\bar y -1) +36 \bar y = \dfrac {37}{s^2+1}##

##\bar y = \dfrac{37}{(s^2+1)(s-6)^2} - \dfrac{12}{(s-6)^2}## will proceed later.
I asked chat gpt to use laplace transform into realising a solution. It is interesting that chat gpt is able to give the steps to a solution... But it is not able to solve the definite integral i.e

##x(t)= 37\int_0^t (ue^{6u})\sin (t-u) du##

Finally, it has indeed solved the problem using laplace transforms (see attached)...let me counter check its steps. Cheers.
 

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Last edited:
chwala said:
I asked chat gpt to use laplace transform into realising a solution. It is interesting that chat gpt is able to give the steps to a solution... But it is not able to solve the definite integral i.e
As you should know, AI chatbots are not allowed as references in PF technical threads. This thread is now closed.
 
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