VinnyCee
- 486
- 0
Homework Statement
Find the phasors of the following time functions:
(a) [tex]v(t)\,=\,3\,cos\left(\omega\,t\,-\,\frac{\pi}{3}\right)[/tex]
(b) [tex]v(t)\,=\,12\,sin\left(\omega\,t\,+\,\frac{\pi}{4}\right)[/tex]
(c) [tex]i(x,\,t)\,=\,2\,e^{-3\,x}\,sin\left(\omega\,t\,+\,\frac{\pi}{6}\right)[/tex]
(d) [tex]i(t)\,=\,-2\,cos\left(\omega\,t\,+\,\frac{3\pi}{4}\right)[/tex]
(e) [tex]i(t)\,=\,4\,sin\left(\omega\,t\,+\,\frac{\pi}{3}\right)\,+\,3\,cos\left(\omega\,t\,-\,\frac{\pi}{6}\right)[/tex]
Homework Equations
A short list of conversions from a larger table in the book. These are conversions from time domain sinusoidal functions on the left to cosine-reference phasor functions on the right.
[tex]A\,cos\left(\omega\,t\,+\,\phi_0\right)\,\,\iff\,\,A\,e^{j\,\phi_0}[/tex]
[tex]A\,sin\left(\omega\,t\,+\,\phi_0\right)\,\,\iff\,\,A\,e^{j\left(\phi_0\,-\,\frac{\pi}{2}\right)}[/tex]
The Attempt at a Solution
(a) [tex]3\,e^{-\frac{\pi}{3}\,j}[/tex]
(b) [tex]12\,e^{j\,\left(\frac{\pi}{4}\,-\,\frac{\pi}{2}\right)}\,=\,12\,e^{-\frac{\pi}{4}\,j}[/tex]
(c) [tex]2\,e^{-3\,x}\,e^{j\,\left(\frac{\pi}{6}\,-\,\frac{\pi}{2}\right)}\,=\,2\,e^{-3\,x}\,e^{-\frac{\pi}{3}\,j}\,=\,2\,e^{-3\,x\,-\,\frac{\pi}{3}\,j}[/tex]
(d) [tex]-2\,e^{\frac{3\pi}{4}\,j}[/tex]
(e) [tex]4\,e^{j\,\left(\frac{\pi}{3}\,-\,\frac{\pi}{2}\right)}\,+\,3\,e^{j\,\left(-\frac{\pi}{6}\right)}\,=\,7\,e^{j\,\left(-\frac{\pi}{6}\right)}[/tex]I have a question especially with (d), the answer is given as...
[tex]-2\,e^{j\,\left(\frac{3\pi}{4}\right)}\,=\,-2\,e^{j\,\left(\frac{\pi}{4}\right)}\,=\,2\,e^{-j\,\left(\frac{\pi}{4}\right)}[/tex]
I don't understand how they did the last two conversions in the given answer! Can someone please explain, and say whether the others are correct as well?
Thanks
Last edited: