MHB Find the possible dimensions for each garden

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The discussion focuses on solving for the dimensions of two similar gardens belonging to Emily and Sarah. Emily's garden width is represented as x, with a length of x+4, while Sarah's garden has a fixed width of y and a length of 18. The relationship between the gardens is established through the equation x/x+4 = y/18, leading to the quadratic equation 18x = x^2 + 8x + 16. This simplifies to x^2 - 10x + 16 = 0, which factors to (x-2)(x-8) = 0, yielding possible values of x as 2 or 8. The thread concludes with gratitude for assistance in solving the problem.
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What I did:
x = Emily's garden's width
x+4 = Emily's garden's length

y= Sarah's garden's width
18 = Sarah's garden's length

y=x+4(as stated in problem)

x/x+4 = y/18(as the two gardens are similar)
Which means that x/x+4 = x+4/18

Now I can't seem to find x
 

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$$\frac{x}{x+4}=\frac{x+4}{18}\implies18x=x^2+8x+16$$

Can you now find $x$?
 
greg1313 said:
$$\frac{x}{x+4}=\frac{x+4}{18}\implies18x=x^2+8x+16$$

Can you now find $x$?

Actually that's where I got to and couldn't go any further
 
$$18x=x^2+8x+16$$

$$x^2-10x+16=0$$

$$(x-2)(x-8)=0$$

$$x=2\text{ or }x=8$$
 
greg1313 said:
$$18x=x^2+8x+16$$

$$x^2-10x+16=0$$

$$(x-2)(x-8)=0$$

$$x=2\text{ or }x=8$$

Thank you so much!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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