Find the probability of energy value after a given measurment

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SUMMARY

The discussion centers on the probability of measuring energy values in quantum mechanics, specifically addressing a scenario where a system's wave function collapses. The participant concludes that the probability of measuring energy value \(E_b\) after measuring \(E_a\) is 0 due to the orthogonality of the states involved. This conclusion is confirmed by another participant, affirming the correctness of the reasoning based on the principles of quantum mechanics.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly wave function collapse
  • Familiarity with the concept of orthogonal states in quantum systems
  • Knowledge of energy eigenstates and their representations
  • Basic grasp of mathematical notation used in quantum mechanics, such as \(e^{\frac{-iE_at_1}{\hbar}}|a \rangle\)
NEXT STEPS
  • Study the implications of wave function collapse in quantum mechanics
  • Explore the mathematical framework of orthogonal states and their significance
  • Learn about energy eigenstates and their role in quantum measurements
  • Investigate the concept of probability amplitudes in quantum mechanics
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Students of quantum mechanics, physicists working on quantum measurement theory, and anyone interested in the mathematical foundations of quantum states and their probabilities.

Taylor_1989
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Homework Statement


I am having a issue conceptualising the problem as I believe the answer is 0.

imageedit_6_7749133169.png

Part c)

Homework Equations

The Attempt at a Solution


My answer is 0 and it for the following reason. A the being say time t=0 the system is in some arbitary state, then when I got to measure the particle at t=t1 the wave function collapse into the ##e^{\frac{-iE_at_1}{\hbar}}|a \rangle## so then as it in this state when I go to measure the particle again the probability of it being ##E_b## is will be 0 as the two states are orthogonal to each other, have I assume the correctly?
 

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Taylor_1989 said:

My answer is 0 and it for the following reason. A the being say time t=0 the system is in some arbitary state, then when I got to measure the particle at t=t1 the wave function collapse into the ##e^{\frac{-iE_at_1}{\hbar}}|a \rangle## so then as it in this state when I go to measure the particle again the probability of it being ##E_b## is will be 0 as the two states are orthogonal to each other, have I assume the correctly?
Yes, that's right.
 

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