Find the Root-Mean-Square of the gas

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Homework Help Overview

The problem involves calculating the root-mean-square speed (vrms) of gas molecules and determining the molar mass of a gas given its density, temperature, and pressure. The context is rooted in the ideal gas law and kinetic molecular theory.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between density and molar mass, questioning how to utilize density in the context of the ideal gas law. There is exploration of substituting density into equations to find molar mass and subsequently vrms.

Discussion Status

Some participants have proposed methods to derive molar mass from density and pressure, while others are confirming the appropriateness of using different values for the gas constant R. There is a mix of interpretations regarding unit conversions and the application of formulas.

Contextual Notes

Participants note the need for unit consistency, particularly regarding pressure and density, and express uncertainty about the best approach to take given the information provided.

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Homework Statement



At 329 K and 1.37 x 10-2 atm, the density of a gas is 1.39 x 10-5 g/cm3. (a) Find vrms for the gas molecules. (b) Find the molar mass of the gas.

Homework Equations



PV = nRT
Vrms = sqrt(3RT/M)

The Attempt at a Solution



I could do this problem right now if there was a molar mass given in the question. How does the density help with finding the answer to the problem? I don't see any examples utilizing it so I'm not sure what to do.
 
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Hint:
Try to find a relation between density and molar mass from the equation PV=nRT
n=m/M , where m is the mass of the gas and M the molar mass
 
All I can see is that density = mass/volume. So you are saying to replace n with m/m? And then set the equation equal to M? So it would be M = mRT/PV and substitite it in for M in the Vrms equation? So then it would be M = D(RT/P) and substitute that in for M in the Vrms equation? Or I guess I could find M right then and there and that gives me answer to part b then just plug M into the Vrms equation and that finds Vrms. Is that basically the solution to this problem?

Pressure in Pascals, density in kg/m^3 right?
 
Last edited:
VitaX said:
Or I guess I could find M right then and there and that gives me answer to part b then just plug M into the Vrms equation and that finds Vrms. Is that basically the solution to this problem?

Its better this way. Use R=0.0821 Lit atm K-1mol-1 because pressure is given in atm. Substitute the 'D' as it is and you will get 'M' in g units

VitaX said:
Pressure in Pascals, density in kg/m^3 right?

Once you find out M in g units, convert it in kg units and plug it in your equation for Vrms. Use R in SI units here.
 
I was always told to conver to Pascals for pressure and use 8.31 J/mol*K for R. But I'm sure either works. I believe what I got is correct. I got M = .027 Kg/mol and Vrms = 497 m/s roughly.
 
VitaX said:
I was always told to conver to Pascals for pressure and use 8.31 J/mol*K for R. But I'm sure either works. I believe what I got is correct. I got M = .027 Kg/mol and Vrms = 497 m/s roughly.
The first value looks good.

Please show your work on the second.
 
M = D(RT/P) = .0127(8.31*268/1030.2) = .027 Kg/mol

Vrms = sqrt(3RT/M) = sqrt(3*8.31*268/.027) = 497.47 m/s
 

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