- #1

albert391212

- 11

- 0

\(\displaystyle f(x)=x^3+4x- 6=0\)

I use Newton's method to solve it

and I also write a program (using excel) for help

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- MHB
- Thread starter albert391212
- Start date

In summary, the equation "f(x)=x^3+4x-6=0" is a polynomial equation with a degree of 3 and has 3 solutions. The solutions can be found using various algebraic methods such as factoring and the quadratic formula, and can be real, imaginary, or complex. Real solutions are values of x that satisfy the equation, while imaginary and complex solutions involve the use of imaginary numbers.

- #1

albert391212

- 11

- 0

\(\displaystyle f(x)=x^3+4x- 6=0\)

I use Newton's method to solve it

and I also write a program (using excel) for help

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- #2

albert391212

- 11

- 0

- #3

albert391212

- 11

- 0

sorry I mistype the function in my programAlbert391212 said:https://www.physicsforums.com/attachments/11796

I tried again using the correct function and put seed 1 , and get the answer x=1.1347

there is only one solution

x=1.1347

- #4

- 2,018

- 816

That's the correct solution. What is your question?

-Dan

-Dan

The equation f(x)=x^3+4x- 6=0 represents a mathematical function where the output (f(x)) is equal to the input (x) cubed, plus four times the input, minus six. The equation is set equal to zero in order to find the points where the function crosses the x-axis, also known as the roots or solutions.

Finding the solution of f(x)=x^3+4x- 6=0 is important because it allows us to determine the x-values where the function crosses the x-axis, which can provide valuable information about the behavior of the function. Additionally, finding the solutions can help us solve real-world problems that involve cubic functions.

To find the solution of f(x)=x^3+4x- 6=0, we need to solve for x by manipulating the equation. This can be done algebraically by factoring or using the cubic formula, or graphically by plotting the function and identifying the x-intercepts. Depending on the complexity of the function, there may be multiple solutions.

In order to solve f(x)=x^3+4x- 6=0, one must have a strong understanding of algebraic manipulation, including factoring and solving equations. It is also important to understand the properties and behavior of cubic functions, such as the number of solutions and how they intersect the x-axis.

Yes, the solution of f(x)=x^3+4x- 6=0 can be found without using algebraic methods by graphing the function and identifying the x-intercepts. However, this method may not be as precise as algebraic methods and may only provide an estimate of the solutions. Additionally, for more complex functions, it may be difficult to accurately determine the solutions graphically.

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