Find the tension in a rope with a 60kg man hanging on one side

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SUMMARY

The discussion focuses on calculating the tension in a rope with a 60 kg man on one side and a 100 kg box on the other side, which is resting on the ground. The correct tension in the rope is established as 603 N, despite initial calculations yielding 735 N. Key equations used include Fnet = Tension - Force of Gravity and m1a = t - m1g, m2a = t - m2g. The participants confirm that the tension remains the same on both sides of the rope, even when considering the normal force acting on the box.

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Homework Statement



Find the tension in a rope with a 60kg man hanging on one side and a 100 kg box on the other side. The box is sitting on the ground.

Homework Equations



Fnet= Tension- Force of Gravity

m1a=t-m1g
m2a=t-m2g

The Attempt at a Solution



I found acceleration which was 2.45, and i plugged it back into formula and got the wrong answer. I know the answer is 603 N, however, i forgot how i came to that answer.
 
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I applied the following :
m1=100 kg , m2=60 kg ,, m1a=m1g-T ,, m2a=T-m2g
(m1+m2)a=m1g-m2g and I get a=2.45 and T=735N in both sides,, so i don't think your answer is wrong ,, but I don't know :P
 
bigboss said:

Homework Statement



Find the tension in a rope with a 60kg man hanging on one side and a 100 kg box on the other side. The box is sitting on the ground.

Homework Equations



Fnet= Tension- Force of Gravity

m1a=t-m1g
m2a=t-m2g

The Attempt at a Solution



I found acceleration which was 2.45, and i plugged it back into formula and got the wrong answer. I know the answer is 603 N, however, i forgot how i came to that answer.

The box is sitting on the ground, so the acceleration is zero.

Note that there is also a normal force on the box.
 
If a = 0 and there is N ,, the Tension of the man is different than the box right ??
m1g-T1-N=0
T2-m2g=0
are these equations right ?
 
Lord Dark said:
If a = 0 and there is N ,, the Tension of the man is different than the box right ??
m1g-T1-N=0
T2-m2g=0
are these equations right ?

The tension on the man is still the same as the tension on the box
The equations are right , but you may set T1 = T2
 

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