# Find the tension in a rope with a 60kg man hanging on one side

## Homework Statement

Find the tension in a rope with a 60kg man hanging on one side and a 100 kg box on the other side. The box is sitting on the ground.

## Homework Equations

Fnet= Tension- Force of Gravity

m1a=t-m1g
m2a=t-m2g

## The Attempt at a Solution

I found acceleration which was 2.45, and i plugged it back into formula and got the wrong answer. I know the answer is 603 N, however, i forgot how i came to that answer.

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I applied the following :
m1=100 kg , m2=60 kg ,, m1a=m1g-T ,, m2a=T-m2g
(m1+m2)a=m1g-m2g and I get a=2.45 and T=735N in both sides,, so i don't think your answer is wrong ,, but I don't know :P

nrqed
Homework Helper
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## Homework Statement

Find the tension in a rope with a 60kg man hanging on one side and a 100 kg box on the other side. The box is sitting on the ground.

## Homework Equations

Fnet= Tension- Force of Gravity

m1a=t-m1g
m2a=t-m2g

## The Attempt at a Solution

I found acceleration which was 2.45, and i plugged it back into formula and got the wrong answer. I know the answer is 603 N, however, i forgot how i came to that answer.
The box is sitting on the ground, so the acceleration is zero.

Note that there is also a normal force on the box.

If a = 0 and there is N ,, the Tension of the man is different than the box right ??
m1g-T1-N=0
T2-m2g=0
are these equations right ?

nrqed