Find the tension in a rope with a 60kg man hanging on one side

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Homework Help Overview

The problem involves calculating the tension in a rope with a 60 kg man hanging on one side and a 100 kg box on the other side, which is resting on the ground. The participants are exploring the implications of the forces acting on both the man and the box.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the equations of motion and the forces acting on both the man and the box, including gravitational forces and tension. There are attempts to calculate acceleration and tension, with some questioning the correctness of their results. Others raise the point that the box being on the ground affects the system's dynamics.

Discussion Status

The discussion is ongoing, with participants sharing their calculations and questioning the assumptions made about the system. Some guidance has been offered regarding the relationship between the tensions on both sides of the rope, but no consensus has been reached on the correct tension value.

Contextual Notes

Participants note that the box is sitting on the ground, which implies that its acceleration is zero. There is also mention of a normal force acting on the box, which may influence the tension calculations.

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Homework Statement



Find the tension in a rope with a 60kg man hanging on one side and a 100 kg box on the other side. The box is sitting on the ground.

Homework Equations



Fnet= Tension- Force of Gravity

m1a=t-m1g
m2a=t-m2g

The Attempt at a Solution



I found acceleration which was 2.45, and i plugged it back into formula and got the wrong answer. I know the answer is 603 N, however, i forgot how i came to that answer.
 
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I applied the following :
m1=100 kg , m2=60 kg ,, m1a=m1g-T ,, m2a=T-m2g
(m1+m2)a=m1g-m2g and I get a=2.45 and T=735N in both sides,, so i don't think your answer is wrong ,, but I don't know :P
 
bigboss said:

Homework Statement



Find the tension in a rope with a 60kg man hanging on one side and a 100 kg box on the other side. The box is sitting on the ground.

Homework Equations



Fnet= Tension- Force of Gravity

m1a=t-m1g
m2a=t-m2g

The Attempt at a Solution



I found acceleration which was 2.45, and i plugged it back into formula and got the wrong answer. I know the answer is 603 N, however, i forgot how i came to that answer.

The box is sitting on the ground, so the acceleration is zero.

Note that there is also a normal force on the box.
 
If a = 0 and there is N ,, the Tension of the man is different than the box right ??
m1g-T1-N=0
T2-m2g=0
are these equations right ?
 
Lord Dark said:
If a = 0 and there is N ,, the Tension of the man is different than the box right ??
m1g-T1-N=0
T2-m2g=0
are these equations right ?

The tension on the man is still the same as the tension on the box
The equations are right , but you may set T1 = T2
 

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