Find the translation and stretch from ##y=2^x## to ##y=2^{x+4}##

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SUMMARY

The discussion centers on the transformation of the function ##y=2^x## to ##y=2^{x+4}##, highlighting both vertical and horizontal shifts. It is established that the transformation involves a horizontal shift of four units to the left, moving the point from (0, 1) to (-4, 1). Additionally, the vertical stretch factor is identified as ##a=16##, leading to the expression ##y=16\cdot 2^x##. The participants clarify that while there is a horizontal shift, the transformation also includes a vertical stretch away from the x-axis.

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  • Understanding of exponential functions, specifically ##y=2^x##
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chwala
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Homework Statement
See attached...
Relevant Equations
Translation/Stretch
1655287826660.png


For part (i) i was thinking of the vertical shift from ##(0,1)## to ##(0,16)##, this can be given by;
##y=2^x + 15## but it does not fit onto ##y=2^{x+4}## something wrong here.

For part (ii), =we have a stretch factor of ##a=16>0## (vertical stretch) thus, ##y=16\cdot 2^x##

your thoughts...i do not have solutions...
 
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If f(x) = 2^x then 2^{x+4} = f(x + 4).
 
pasmith said:
If f(x) = 2^x then 2^{x+4} = f(x + 4).
Isn't this a horizontal shift... it's not exactly what we want. Unless I am missing something...
 
chwala said:
For part (i) i was thinking of the vertical shift from (0,1) to (0,16),
As already noted, the transformation is a horizontal translation (or shift). The original graph is translated four units to the left. The point on the original graph that was at (0, 1) is now at (-4, 1). The point that was at (4, 16) is now at (0, 16).
chwala said:
Isn't this a horizontal shift...
Yes.
 
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On the other hand, ##2^{x + 4} = 2^x \cdot 2^4 = 16\cdot 2^2##.
Viewed this way there is a vertical stretch away from the x-axis.
 
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