Find the value of a capacitor given percent of the initial value

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SUMMARY

The discussion focuses on calculating the value of a capacitor discharging through an 80.0 ohm resistor, where the discharge current drops to 23.0% of its initial value in 1.50 ms. The relevant equation used is \(t = RC\), leading to the calculation of \(RC = 6521.74\). The capacitor value is derived as \(C = \frac{6521.74}{80} = 81.5 \, \mu F\). However, this calculation is identified as incorrect, prompting a request for assistance.

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  • Understanding of capacitor discharge equations
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  • Knowledge of exponential decay functions
  • Basic algebra for solving equations
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Homework Statement



A capacitor is discharged through an 80.0 ohm resistor. The discharge current decreases to 23.0% of its initial value in 1.50ms .

What is the value of the capacitor?

Homework Equations



t=RC

The Attempt at a Solution



1500 μs = 0.23 RC
RC= 6521.74

C= 6521.74/R

C= 6521.74/80 = 81.5 μF


This is not correct... Please help! It's due within the next thirty minutes!
 
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The voltage vs time graph is not linear.
$$v(t)=V_0e^{-t/RC}$$
 

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