Maximum current through a capacitor

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SUMMARY

The discussion focuses on calculating the maximum current through a capacitor when discharged through a resistor. A 2200 µF capacitor charged to 12 V is discharged through a 16 Ω resistor, yielding a time constant of 35 ms. The maximum current is incorrectly estimated at 0.75 A, highlighting the need for clarity in applying Ohm's Law (V = IR) and understanding the role of the electric motor in the energy transfer process. Correct calculations must consider the initial conditions and the discharge characteristics of the capacitor.

PREREQUISITES
  • Understanding of capacitor discharge principles
  • Knowledge of Ohm's Law (V = IR)
  • Familiarity with time constant calculations (RC)
  • Basic concepts of energy transfer in electric circuits
NEXT STEPS
  • Calculate maximum current using the formula I = V/R with correct parameters
  • Explore the relationship between energy stored in capacitors and work done by electric motors
  • Learn about transient response in RC circuits
  • Investigate the effects of varying resistance on capacitor discharge rates
USEFUL FOR

Students in electrical engineering, hobbyists working with capacitors and motors, and anyone studying circuit analysis and energy transfer in electrical systems.

FelaKuti
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Homework Statement


A 2200 µF capacitor is charged to a potential difference of 12 V and then discharged through an electric motor. The motor lifts a 50 g mass through a height of 24 cm.
The capacitor is charged to 12 V again and then discharged through a 16 Ω resistor
Determine the time constant and the maximum current flowing through the circuit.

Homework Equations


[/B]
C = Q/v
RC = t
V = IR

The Attempt at a Solution



The time constant would be RC = 35ms
I feel like this should be really simple but I can't figure out the maximum current. I know when a capacitor charges or discharges the current is initially at a maximum then falls. If the maximum voltage across the resistor is 12V, then I figure the maximum current flowing would be 0.75A but that's wrong.
 
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Did you use the information about the electric motor? If so, how?
 

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