1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Find the value of the emf in a battery

  1. Apr 12, 2009 #1
    1. The problem statement, all variables and given/known data

    A real battery is not just an emf. We can model a real 1.5 battery as a 1.5 emf in series with a resistor known as the "internal resistance", as shown in the figure (Intro 1 figure) . A typical battery has 1.0 Ohm internal resistance due to imperfections that limit current through the battery. When there's no current through the battery, and thus no voltage drop across the internal resistance, the potential difference between its terminals is 1.5 V, the value of the emf. Suppose the terminals of this battery are connected to a 3.0 Ohm resistor.
    a) What is the potential difference between the terminals of the battery?

    b) What fraction of the battery's power is dissipated by the internal resistance?

    2. Relevant equations

    V = IR

    3. The attempt at a solution
     
  2. jcsd
  3. Apr 12, 2009 #2
    Re: Battery

    here is the pic
     

    Attached Files:

    • 1.jpg
      1.jpg
      File size:
      12.1 KB
      Views:
      252
  4. Apr 13, 2009 #3
    Re: Battery

    Yes you do need V=IR but show your attempt to use it.
     
  5. Apr 13, 2009 #4
    Re: Battery

    V = IR
    I = V/R = 1.5 V/1 Ohm = 1.5 A

    so for 3 Ohm resistor voltage difference, V = IR = 1.5 A*3 Ohm = 4.5 V

    Right?
     
  6. Apr 13, 2009 #5
    Re: Battery

    I=V/R but when the resistor is connected the total resistance=4 ohms.The same current flows through The internal resistance of the battery and the 3 ohm resistor.From this you should be able to work out part a which can be looked at in two ways.
    1.The voltage across the 3 ohm resistor
    2.The emf minus the voltage dropped across the internal resistance
    Sketch the circuit,mark in the voltages and their polarities and you should see why the two answers are the same.
    Try it out and show what you get.
     
  7. Apr 13, 2009 #6
    Re: Battery

    so the resistance is 4 ohm and the voltage is 1.5 V
    so I = V/R = 1.5/40 = 0.375 A
    right?
     
  8. Apr 14, 2009 #7
    Re: Battery

    Right, now you should be able to finish it off.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Find the value of the emf in a battery
  1. Emf of a battery (Replies: 4)

Loading...