1. The problem statement, all variables and given/known data A battery of emf 2V and internal resistance 0.1ohm is being charged with a current of 5 ampere. In what direction will the current flow inside the battery?What is the potential difference between the two terminals of the battery? 2. Relevant equations If a battery of emf E and an internal resistance r has a current i flowing through it,potential difference across it's terminals,say V is defined as: V=E-ir 3. The attempt at a solution When we connect a battery in a circuit,INSIDE THE BATTERY,current flows from the negative terminal to the positive terminal,which discharges the battery(correct me if I'm wrong here plz) So,while recharging,the direction should be reversed,shouldn't it? Also,the formula stated above,yields the answer to be 1.5V But,the answer given is: Current flows from the anode to the cathode V.d=2.5 Volts I am guessing if I just get the reasoning for the first part,the formula stated could be modifed to yield the correct answer,but why does the current inside the battery flow from the negative terminal to the positive terminal,wouldn't that discharge the battery?