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tony873004

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The region bounded by the curves is rotated about the specified axis. Find the volume of th eresulting solid by and method.

[tex]x^2 + \left( {y - 1} \right)^2 = 1[/tex]

First question want it rotated about the x-axis, the second question wants it rotated about the y-axis.

So I re-write it in terms of x. Seems easier than in terms of y since there's only 1 x term.

[tex]x = \sqrt { - y^2 + 2y}

[/tex]

The problem is when I graph it,

So nothing is bounded. There is no solid to rotate. Should I have solved in terms of y instead? How would I do that?

[tex]x^2 + \left( {y - 1} \right)^2 = 1[/tex]

First question want it rotated about the x-axis, the second question wants it rotated about the y-axis.

So I re-write it in terms of x. Seems easier than in terms of y since there's only 1 x term.

[tex]x = \sqrt { - y^2 + 2y}

[/tex]

The problem is when I graph it,

So nothing is bounded. There is no solid to rotate. Should I have solved in terms of y instead? How would I do that?

## Homework Statement

## Homework Equations

## The Attempt at a Solution

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