MHB Find the volume using shell and disk method

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The discussion revolves around calculating the volume using the shell and disk methods, with a focus on a specific volume expression involving 18π. The user is confused about the origin of the 18π term in their volume calculations. It is clarified that the volume of a hemisphere formula, which is 2πr³/3, applies here with r set to 3, leading to a total volume of 18π. The user seeks assistance in understanding the integration steps and confirming the correctness of their calculations. The conversation emphasizes the importance of correctly applying volume formulas and integration techniques.
jaychay
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Can you please help me ?
I have tried to do it but I end up getting the wrong answer.

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$\displaystyle V = 18\pi - 2\pi \int_0^{\pi/2} x \cos{x} \, dx$

$\displaystyle V = 18\pi - \pi \int_0^1 [\arccos{y}]^2 \, dy$
 
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skeeter said:
$\displaystyle V = 18\pi - 2\pi \int_0^{\pi/2} x \cos{x} \, dx$

$\displaystyle V = 18\pi - \pi \int_0^1 [\arccos{y}]^2 \, dy$
Can you tell me where did 18 pi come from ?
 
jaychay said:
Can you tell me where did 18 pi come from ?

volume of a hemisphere is $\dfrac{2\pi r^3}{3}$ and $r = 3$
 
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