Find time given velocity and distance

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SUMMARY

The discussion focuses on calculating the time a vehicle takes to stop and the time a pedestrian has to escape when a vehicle is traveling at 28 m/s and requires 29 m to stop. The acceleration produced by braking is determined to be 13.52 m/s². The key equations used include v = vo + at, x - xo = vot + ½at², and v² = vo² + 2a(x - xo). The main question revolves around finding the time it takes for the vehicle to cover 27 m before it stops.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Basic knowledge of acceleration and deceleration concepts
  • Familiarity with units of measurement (meters, seconds)
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Calculate time using the equation x - xo = vot + ½at²
  • Explore the implications of different braking distances on pedestrian safety
  • Study real-world applications of kinematic equations in vehicle dynamics
  • Investigate factors affecting stopping distance, such as road conditions and vehicle weight
USEFUL FOR

Students studying physics, automotive engineers, and safety analysts focusing on vehicle stopping distances and pedestrian safety measures.

Calhoun295
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Homework Statement



A certain vehicle requires a distance of 29 m to stop when it is traveling at 28 m/s.
(a) What magnitude of acceleration is produced by braking under these conditions?
(b) If a jaywalker is 27 m in front of the vehicle when the driver first applies the brakes, how much time does the pedestrian have to get out of the way?

Homework Equations



v=vo + at
x - xo = vot + [tex]\frac{1}{2}[/tex]at2
v2 = vo2 + 2a(x - xo)

are the given equations for what we're learning.

The Attempt at a Solution



(a) 13.52m/s2
(b) is what I cannot find
 
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I'll rephrase the question: How long does it take the vehicle to cover 27 m?
 

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