1. The problem statement, all variables and given/known data A car accelerates uniformly and reaches a speed of 4.40 m/s in 8.00 seconds. Calculate the distance traveled by the car from a time of 1.40 to 4.70 seconds. 2. Relevant equations x = xo + vo t + ½ a t^2 (v-vo)/t=a 3. The attempt at a solution (v-vo)/t=a (4.40 m/s - 0 m/s)/8.00s=a .550 m/s^2=a x = xo + vo t + ½ a t^2 x= 0 + 0(3.30s) + 1/2 (.550 m/s^2) (3.30s)^2 x= 3.00 meters My homework is on LON-CAPA, an online program and when I enter 3.00 meters it states the answer is incorrect. I've been working on this problem for 2 hours and can't come up with any other answer.