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## Homework Statement

A car accelerates uniformly and reaches a speed of 4.40 m/s in 8.00 seconds. Calculate the distance traveled by the car from a time of 1.40 to 4.70 seconds.

## Homework Equations

x = xo + vo t + ½ a t^2

(v-vo)/t=a

## The Attempt at a Solution

(v-vo)/t=a

(4.40 m/s - 0 m/s)/8.00s=a

.550 m/s^2=a

x = xo + vo t + ½ a t^2

x= 0 + 0(3.30s) + 1/2 (.550 m/s^2) (3.30s)^2

x= 3.00 meters

My homework is on LON-CAPA, an online program and when I enter 3.00 meters it states the answer is incorrect. I've been working on this problem for 2 hours and can't come up with any other answer.