Find translational Ke Rotational Ke

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SUMMARY

The discussion focuses on calculating translational and rotational kinetic energy (Ke) for a basketball weighing 0.5 kg with a radius of 0.1 m, rolling at a speed of 2.0 m/s. The translational kinetic energy is calculated as 1 J using the formula translational ke = 1/2mv^2. The participants discuss the appropriate moment of inertia for a basketball, noting that a solid sphere's inertia is I = 2/5 MR^2 and a hollow sphere's inertia is I = 2/3 MR^2. Additionally, they explore the relationship between translational and rotational speeds.

PREREQUISITES
  • Understanding of kinetic energy formulas: translational and rotational
  • Knowledge of moment of inertia for different shapes
  • Familiarity with angular momentum concepts
  • Basic physics principles regarding rolling motion
NEXT STEPS
  • Research the moment of inertia for various geometrical shapes
  • Learn how to convert between translational and rotational speeds
  • Study the implications of rolling without slipping
  • Explore advanced kinetic energy calculations in complex systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts of kinetic energy and rotational motion.

blackout85
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Homework Statement



A basketball weighs 500grams or (.5 kg) it has a radius of 10cm (.10 m) and is rolling at 2.0 m/s. Find translational Ke Rotational Ke Translational momentum and Rotational momentum.


Homework Equations


translational ke= 1/2mv^2
rotational ke = 1/2Iw^2 ( I am unsure of what inertia equation to use for a basketball)
Translational momentum= mv^2
rotational ke = iw

The Attempt at a Solution



Translational ke = 1/2 mv^2= .5(.5kg)(2.0m/s)^2= 1 J
I think I know how to do the equations I just don't know what equation to use for the rotational inertia for a basketball, if someone could help me on that. Thanks :redface:
 
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blackout85 said:

Homework Statement



A basketball weighs 500grams or (.5 kg) it has a radius of 10cm (.10 m) and is rolling at 2.0 m/s. Find translational Ke Rotational Ke Translational momentum and Rotational momentum.


Homework Equations


translational ke= 1/2mv^2
rotational ke = 1/2Iw^2 ( I am unsure of what inertia equation to use for a basketball)
Translational momentum= mv^2
rotational ke = iw
I think you mean L = angular momentum = [itex]I\omega[/itex]

The Attempt at a Solution



Translational ke = 1/2 mv^2= .5(.5kg)(2.0m/s)^2= 1 J
I think I know how to do the equations I just don't know what equation to use for the rotational inertia for a basketball, if someone could help me on that.
The moment of inertia of a solid or hollow sphere is a calculus problem. It works out to [itex]\frac{2}{5}MR^2[/itex] for a solid sphere and [itex]\frac{2}{3}MR^2[/itex] for a hollow sphere (see the http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html#cmi"). Which one would you use?

How do you determine the rotational speed from the translational speed? ie. how long does it take the ball to roll 360 degrees or [itex]2\pi[/itex] radians?

AM
 
Last edited by a moderator:
This should serve as a clue: http://www.physics.upenn.edu/courses/gladney/mathphys/java/sect4/subsubsection4_1_4_3.html" .

Edit: oops, late.
 
Last edited by a moderator:

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