Calculating Velocity at the Bottom of a Quarter Circle Track

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Homework Help Overview

The problem involves a block of mass sliding down a frictionless quarter circle track, with an initial downward velocity and the goal of determining its velocity at the bottom of the track. The subject area includes concepts of energy conservation, kinetic energy, and potential energy.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of energy conservation principles, questioning how to incorporate both rotational and translational kinetic energy. There is uncertainty about the relationship between the radius of the track and the height of the mass at the top.

Discussion Status

Some participants have offered guidance on thinking intuitively about the problem, while others have expressed confusion regarding the relationship between the radius and height. There is an acknowledgment of a correct numerical result, but questions about the underlying assumptions remain unresolved.

Contextual Notes

Participants are navigating the implications of the problem's setup, particularly regarding the geometry of the track and the definitions of kinetic and potential energy. The visual representation of the track is noted to be misleading in terms of scale.

tennisgirl92
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Homework Statement


A block of mass 10kg starts at the top of a frictionless track which forms a quarter circle with radius 10m. It is given an initial downward velocity of 10m/s. What is the velocity at the bottom of the track?

Homework Equations


KEtranslational, f+ KErotational, f+PEf=KEtranslational, i+KErotational, i+ PEf
KE, rotational=1/2Iw2
KE, translational=1/2mv2
PE=mgh
I=MR2
w=v/r

The Attempt at a Solution


I believe the initial equation would be set up like this.
1/2mvf2+ 1/2 MR2(V/R)2+mghf=1/2mvi2+1/2 MR2(V/R)2+mghi

which would then reduce to:
vf2=vi2+ghinitial

This does not seem like the likely way to do it because we are not given the height of the mass at the top. Should I be using the rotational and translational KE in the equation? At what point is it rotational and what point translational?
 
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tennisgirl92 said:
vf2=vi2+ghinitial

This does not seem like the likely way to do it because we are not given the height of the mass at the top.

Look carefully.

tennisgirl92 said:
Should I be using the rotational and translational KE in the equation? At what point is it rotational and what point translational?

Why would it rotate? When does something rotate?
 
Mastermind01 said:
Look carefully.Why would it rotate? When does something rotate?

Would the radius be the initial height?

When it is rolling? I'm not exactly sure.
 
tennisgirl92 said:
Would the radius be the initial height?

That is correct.

tennisgirl92 said:
When it is rolling? I'm not exactly sure.

Try and think intuitively if you don't know the physics behind it.
 
Mastermind01 said:
That is correct.
Try and think intuitively if you don't know the physics behind it.
Ok, now I see how to do this. I obtained 17.2 m/s, which is correct. Thank you!

However, I still don't see how the radius could be equal to the height of the ramp. There is a picture provided that looks like a skateboard ramp, with a strict vertical height and then the inside being curved with a radius. The vertical height does not look equal to the radius, even though I know this is not to scale.
 
Does the picture below look like the picture you have of the skateboard ramp? Is the quarter circle oriented like that?
Quarter circle track.jpg
 
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TomHart said:
Does the picture below look like the picture you have of the skateboard ramp? Is the quarter circle oriented like that?View attachment 197493
yes, it is just like that, except flipped so that the curve is on the right and height on the left.
 
So does it make sense to you that the radius = height?
 
Yes, I do see it now-my picture did not have the radius being pointed horizontally and vertically, just down the middle. Thank you for all your help!
 
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