Find Unit Vector for 3-D Orthogonal RH System

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SUMMARY

The discussion focuses on finding unit vectors in a 3-dimensional orthogonal right-handed coordinate system using the vectors a = 2i - 3j - 3k and b = 6i + 2j + k. The cross product of vectors a and b, denoted as v = a × b, results in the vector v = 3i - 20j + 22k, which is perpendicular to both a and b. To obtain unit vectors, the final step involves normalizing the vectors a, v, and a third vector c, which is calculated as c = a × v.

PREREQUISITES
  • Understanding of vector operations, specifically cross products
  • Familiarity with 3D coordinate systems and orthogonality
  • Knowledge of vector normalization techniques
  • Basic proficiency in vector notation and manipulation
NEXT STEPS
  • Learn about vector normalization and its applications in 3D graphics
  • Study the properties of orthogonal coordinate systems in linear algebra
  • Explore the significance of the right-hand rule in vector cross products
  • Investigate advanced vector operations, such as triple products and their geometric interpretations
USEFUL FOR

Students in physics or mathematics, particularly those studying vector calculus, as well as professionals in fields requiring 3D modeling and simulations, such as computer graphics and engineering.

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Homework Statement


Two vectors are given by the relations

a = 2i-3j-3k
b = 6i+2j+k

Find unit vectors corresponding to a 3- dimensional orthogonal right handed coordinate system where one of the axes is parallel to _{}a and another of the axes is perpendicular to _{}b

Homework Equations




Cross rule: AXB = C

The Attempt at a Solution




I know from cross product that if we have two vectors in a plane then their multiple vector will also be perpendicular to them. So my vector AXB is : 3i-20j+22k ( perpendicular to a and b )

Now I know they want unit vector which is : v/ magnitude of v but in the above case I was told to find the vector : Ax(AXB)...
I am confused about this point. Can anyone clarify for me. Thanks
 
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You are given a and b and asked to find "one unit vector that is parallel to a"- that should be easy- and another that perpendicular to b. As you say, axb is perpendicular to both a and b and so to b. You are then asked to find a third vector, c, say, that is perpendicular to both a and the new vector you just calculated. Yes, that is ax(axb). There is no problem with that- just do it! First find v= axb, then use that to find c= axv. I recommend first finding the vectors v and c and then dividing a, v, and c by their lengths to get unit vectors.
 

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