Find unknown element in a matrix

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SUMMARY

The discussion centers on finding values of 'a' for which the columns of the matrix are linearly dependent. The matrix in question is given as (2, 0, 8; -4, 7, a; 1, -3, 4). Through the reduced row echelon form (RREF), it is determined that the only value of 'a' that results in linear dependence is a = -16. For any other value of 'a', the columns remain linearly independent.

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Homework Statement


Find all values of a for which the columns of the matrix are linearly dependent.

<br /> \left( {\begin{array}{*{20}c}<br /> 2 &amp; 0 &amp; 8 \\<br /> { - 4} &amp; 7 &amp; a \\<br /> 1 &amp; { - 3} &amp; 4 \\<br /> \end{array}} \right)<br />


Homework Equations





The Attempt at a Solution


So I took of rref of the matrix and found

<br /> \left( {\begin{array}{*{20}c}<br /> 1 &amp; 0 &amp; 4 \\<br /> { - 0} &amp; 1 &amp; 0 \\<br /> 0 &amp; { 0} &amp; a+16 \\<br /> \end{array}} \right)<br />

So then I have
a+16=0
a = -16


So that gives me 1 value which makes the columns of the matrix linearly dependent, but how do I find the other ones, or even know if more exist?

Thanks
 
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RedXIII said:

Homework Statement


Find all values of a for which the columns of the matrix are linearly dependent.

<br /> \left( {\begin{array}{*{20}c}<br /> 2 &amp; 0 &amp; 8 \\<br /> { - 4} &amp; 7 &amp; a \\<br /> 1 &amp; { - 3} &amp; 4 \\<br /> \end{array}} \right)<br />


Homework Equations





The Attempt at a Solution


So I took of rref of the matrix and found

<br /> \left( {\begin{array}{*{20}c}<br /> 1 &amp; 0 &amp; 4 \\<br /> { - 0} &amp; 1 &amp; 0 \\<br /> 0 &amp; { 0} &amp; a+16 \\<br /> \end{array}} \right)<br />

So then I have
a+16=0
a = -16


So that gives me 1 value which makes the columns of the matrix linearly dependent, but how do I find the other ones, or even know if more exist?

Thanks

You've got it. There is just the one value, a=(-16). Otherwise the columns of the reduced matrix are linearly independent.
 

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