What is the value of capacitance C?

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The equivalent capacitance of the circuit is given as 9.22 microFarads, and the problem involves a combination of series and parallel capacitors. The correct approach requires simplifying the circuit step by step, first resolving the series and parallel combinations accurately. An error was identified in the initial calculation, particularly in how the capacitors were combined, leading to an incorrect value for capacitance C. The correct sequence of calculations must be followed to achieve the expected result of approximately 2.558 microFarads. Proper attention to the order of operations and the arrangement of capacitors is crucial for accurate results.
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Homework Statement


The equivalent capacitance of the capacitors shown in Figure 21-41 is 9.22 microFarads. Find the value of capacitance C.

Homework Equations


Ok so this has to deal with Ceq, and it is a combonation of series and parallel circuits. Knowing this, I can use for series 1/Cs=(1/C1)+(1/C2) and so on. For parallel, it is Cp=C1+C2 and so on.

The Attempt at a Solution


Looking at the picture, the givens is Ceq = 9.22 microFarads. I first simplify the circuit so that it shows 3 parallel circuits, which are 7.22 microFarads, ((4.25C)/(4.25+C),and 4.92. Setting up the equation, i get C to equal something not 2.56 microfarads. What did i do wrong?
 

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help me pls said:
3 parallel circuits, which are 7.22 microFarads, ((4.25C)/(4.25+C),and 4.92.
I would calculate that again (there's an error here). Look at the circuit carefully.
(btw. you SHOULD get 2,558microF)
 
Not exactly 3 parallel circuits but 7.22 in parallel with (C in series with (4.25 in parallel with (12.0 in series with 8.35)))
 
That's correct but you have to resolve them in the right order taking into account the brackets eg...

"12.0 in series with 8.35"
then
"4.25 in parallel with" the above
then
"C in series with" the above
etc

However this bit..
help me pls said:
((4.25C)/(4.25+C),
suggests you did
"C in series with 4.25"
or something like that.
 
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