I am having trouble simplifying a circuit of capacitors that I was given. I am asked to determine the equivalent capacitance of the combination below (attached photo).
Capacitors in series: 1/Ceq = 1/C1+1/C2+....
Capacitors in parallel: Ceq = C1 + C2 +.....
The Attempt at a Solution
(1) Attempt #1 in my diagram would involve putting capacitor 1F and 2F in series, which would create equivalent capacitors of 2/3F each. Then I would find the equivalent capacitance in parallel: 2/3+2/3+3 = 4.33F
(2) Attempt #2 in my diagram involves a different approach... where both 1F capacitors are in parallel, join again at 3F, and break into a parallel circuit again for the 2F capacitors.
This would simplify into 1F, 3F, and 4F in series, giving Ctotal=1.583F
Which simplified circuit would be correct? (If either of these...)