Find Values of c and f that make h continuous

  • Thread starter Thread starter Painguy
  • Start date Start date
  • Tags Tags
    Continuous
Click For Summary

Homework Help Overview

The problem involves determining the values of constants c and d in a piecewise function h(x) to ensure continuity at specified points. The function is defined differently for intervals of x, and continuity must be checked at the transition points x=1 and x=2.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss taking limits of the function at the transition points and setting them equal to each other to find relationships between c and d. There is uncertainty about how to proceed after establishing the equations derived from the limits.

Discussion Status

Some participants have derived two linear equations from their evaluations but express uncertainty about solving them. There is a mix of support and frustration in the responses, indicating a range of understanding among participants.

Contextual Notes

One participant expresses concern about their ability to solve the linear equations, suggesting a potential gap in confidence or understanding of basic algebraic concepts.

Painguy
Messages
118
Reaction score
0

Homework Statement


{ 2x if x<1
h(x)= { cx^2+d if 1<=x<=2
{ 4x if x>2


Homework Equations





The Attempt at a Solution


It tried taking the limit of 2x and cx^2+d at x->1 (from both sides) and set them equal to each other. I did the same for 2 as well, but i got stuck after that.
 
Physics news on Phys.org
What did you get after you did that??
 
After evaluating those 2 i get 2=c+d and 8=4c+d. I'm not quite sure what to do now
 
Painguy said:
After evaluating those 2 i get 2=c+d and 8=4c+d. I'm not quite sure what to do now

Are you saying that you do not know how to solve two simple linear equations in two unknowns? Have you really never, ever, seen problems like that before?

RGV
 
Ray Vickson said:
Are you saying that you do not know how to solve two simple linear equations in two unknowns? Have you really never, ever, seen problems like that before?

RGV

OH well I am blind...excuse my stupidity thank you for your help
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
22
Views
2K
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 27 ·
Replies
27
Views
2K