Find Velocity given Force and Mass

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To find the velocity of a 4.80 kg object subjected to a time-varying force, the relationship F = ma can be used to derive acceleration. The formula v = at can be adapted to v_final = (Ft)/m, where Ft represents the integral of force over time. The object's velocity at t = 6 seconds is determined to be 4.17 m/s, which remains constant after 4 seconds due to the absence of force. Understanding the area under the force-time graph is crucial for solving similar problems. Mastery of these concepts is essential for tackling related questions on tests.
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Homework Statement



A 4.80 kg object initially at rest at the origin is subjected to the time-varying force shown in the figure

What is the object's velocity at t =6 s ?

Homework Equations



F = ma ?

The Attempt at a Solution



I guessed that the answer was 4.17 m/s (by doing a lot of googling), which was correct but i have no idea how to do this problem if it were on a test.
 

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Well, There is a formula which states that

v=at

where v is the final velocity, a is the (average) acceleration and t is the time the body accelerates.

This is a pretty intuitive formula if you think a little bit about it. The acceleration is unknown, but you can express it in terms of F and m (since you know that F=ma)

Combining these gives

v_{final}=\frac{F}{m} t

This we can write as

v_{final}=\frac{Ft}{m}

Ft represents the integral (area under the graph) from 0-4 seconds. If/after you study more differential math this will also be intuitive.

Does this help?

Notice that the body doesn't accelerate after 4 seconds, since no force acts on it, and thus its speed stays constant. In other words the body has the same speed at 4 seconds and 6 seconds (if opposing forces are assumed to be small)
 
Last edited:
alexas said:
A 4.80 kg object initially at rest at the origin is subjected to the time-varying force shown in the figure

What is the object's velocity at t =6 s ?

I guessed that the answer was 4.17 m/s (by doing a lot of googling), which was correct but i have no idea how to do this problem if it were on a test.

Hi alexas! :smile:

I assume you knew that F = ma, or force = mass times acceleration, and so you could get the acceleration from the graph by dividing by 4.8

ok … draw a new graph (in your mind, if you like) …

it has acceleration against time …

how can you find the velocity just by looking at that graph? :smile:
 
Velocity is the speed at which an object is moving. It can also be thought of as the speed of a moving object divided by the time of travel. In this case, it is the speed of a body divided by the time taken for the body to move a given distance. This can be expressed mathematically as: v = v 0 t $${\displaystyle v=v_{0}t}$$ where: v = velocity ( m / s or km / h ) v 0 = initial velocity ( m / s or km / h ) t = time ( s or h ) v = final velocity ( m / s or km / h )
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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