Find Velocity given Force and Mass

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Homework Help Overview

The discussion revolves around determining the velocity of a 4.80 kg object subjected to a time-varying force, starting from rest at the origin. Participants are exploring the relationship between force, mass, and acceleration to find the object's velocity at a specific time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula relating force, mass, and acceleration, questioning how to apply it to find velocity. Some suggest using the integral of force over time to determine acceleration, while others explore the implications of the force graph on velocity.

Discussion Status

There is an ongoing exploration of different methods to approach the problem, with some participants providing insights into the relationship between force and acceleration. However, no consensus has been reached on a specific method or solution.

Contextual Notes

Participants note the challenge of applying theoretical concepts to practical problems, particularly in a test scenario. There is also mention of the assumption that opposing forces are negligible after a certain time period.

alexas
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Homework Statement



A 4.80 kg object initially at rest at the origin is subjected to the time-varying force shown in the figure

What is the object's velocity at t =6 s ?

Homework Equations



F = ma ?

The Attempt at a Solution



I guessed that the answer was 4.17 m/s (by doing a lot of googling), which was correct but i have no idea how to do this problem if it were on a test.
 

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Well, There is a formula which states that

v=at

where v is the final velocity, a is the (average) acceleration and t is the time the body accelerates.

This is a pretty intuitive formula if you think a little bit about it. The acceleration is unknown, but you can express it in terms of F and m (since you know that F=ma)

Combining these gives

v_{final}=\frac{F}{m} t

This we can write as

v_{final}=\frac{Ft}{m}

Ft represents the integral (area under the graph) from 0-4 seconds. If/after you study more differential math this will also be intuitive.

Does this help?

Notice that the body doesn't accelerate after 4 seconds, since no force acts on it, and thus its speed stays constant. In other words the body has the same speed at 4 seconds and 6 seconds (if opposing forces are assumed to be small)
 
Last edited:
alexas said:
A 4.80 kg object initially at rest at the origin is subjected to the time-varying force shown in the figure

What is the object's velocity at t =6 s ?

I guessed that the answer was 4.17 m/s (by doing a lot of googling), which was correct but i have no idea how to do this problem if it were on a test.

Hi alexas! :smile:

I assume you knew that F = ma, or force = mass times acceleration, and so you could get the acceleration from the graph by dividing by 4.8

ok … draw a new graph (in your mind, if you like) …

it has acceleration against time …

how can you find the velocity just by looking at that graph? :smile:
 
Velocity is the speed at which an object is moving. It can also be thought of as the speed of a moving object divided by the time of travel. In this case, it is the speed of a body divided by the time taken for the body to move a given distance. This can be expressed mathematically as: v = v 0 t $${\displaystyle v=v_{0}t}$$ where: v = velocity ( m / s or km / h ) v 0 = initial velocity ( m / s or km / h ) t = time ( s or h ) v = final velocity ( m / s or km / h )
 

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