Find Volume b/w 2 Surfaces: x, y, z Equations

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SUMMARY

The discussion focuses on calculating the volume between two surfaces defined by the equations z = 2x² + y² and z = 4 - y². The intersection of these surfaces occurs at a circle described by the equation x² + y² = 2, indicating a radius of √2. The bounds for integration are established as x ranging from -√2 to √2, y from -√2 - x² to √2 - x², and z from 4 - y² to 2x² + y². The use of cylindrical coordinates is suggested due to the circular symmetry of the problem.

PREREQUISITES
  • Understanding of triple integrals in calculus
  • Familiarity with surface equations and their intersections
  • Knowledge of cylindrical coordinates
  • Ability to set integration bounds for multivariable functions
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  • Study the application of triple integrals in volume calculations
  • Learn about cylindrical coordinates and their advantages in integration
  • Explore the method of finding intersection points of surfaces
  • Practice setting up and evaluating integrals with varying bounds
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Students in calculus courses, particularly those studying multivariable calculus, as well as educators and tutors assisting with volume calculations between surfaces.

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Homework Statement



Find the volume between the two surfaces

z = 2x^2 + y^2

z = 4 - y^2

Homework Equations





The Attempt at a Solution



Ok so i found out that the surfaces intersect at a circle. When i solved i got

x^2 + y^2 = 2, so the circle has a radius of sqrt 2.

So these are the bounds i got. X goes from - sqrt 2 to sqrt 2, y goes from - sqrt 2-x^2 to sqrt 2-x^2 and z goes from 4-y^2 to 2x^2 + y^2.

Is that right? If so, what is the equation I am integrating? Is it always integrating 1 dx dy dz?
 
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That would certainly work. And what would be the bounds on the z-integral?


(Also, because of the circular symmetry, I would be inclined to use cylindrical coordinates- but you certainly can do it the way you suggest.)
 

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