Find Width of Rectangle with 600yd2 and 140yd Fencing

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The problem involves determining the width of a rectangular enclosure with an area of at least 600 yd² and a maximum fencing length of 140 yd. The width (w) must not exceed the length (L), leading to the inequality (70 - w)w ≥ 600. The valid width range is established as 10 ≤ w ≤ 35, ensuring that the conditions of the problem are satisfied. The solution confirms that the only feasible width candidates are 10 and values up to 35, with the maximum width being constrained by the area requirement.

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A rectangular enclosure must have an area of at least 600 yd2. If 140 yd of fencing is to be used, and the width cannot exceed the length, within what limits must the width of the enclosure lie?
Select one:
A. 35 ≤ w ≤ 60
B. 10 ≤ w ≤ 35
C. 10 ≤ w ≤ 60
D. 0 ≤ w ≤ 10
 
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length, $L$ and width $(70-L)$

constraints ...

$70-L \le L$

$L(70-L) \ge 600$

see what you can do from here
 
Last edited by a moderator:
Since the problem specifically asks about "w", the width, I would, instead, say that $(70- w)w\ge 600$.

Of course that's exactly the same as the inequality skeeter gave for L. There will be two solutions. It is the condition that "the width cannot exceed the length" that allows you to distinguish between them.
 
Width being less than square root of 600 I see that it is less than 25 so I have only one candidate d to check and width 10 so length 60 meets the criteria and hence the answer
 

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