Finding a basis for the range space

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    Basis Range Space
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SUMMARY

The discussion centers on determining a basis for the range space of a vector space V with a dimension of 3. The proposed basis vectors {(1,1,1,2), (1,2,-3,1), (3,4,-1,5)} are incorrectly assumed to be linearly independent. Participants clarify that these vectors are actually linearly dependent, and thus cannot serve as a valid basis. It is emphasized that selecting any three other columns from the matrix can yield an independent set suitable for a basis.

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Janiceleong26
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1. Homework Statement
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I've found the dimension of V to be 3.
According to the solutions, it seems that the basis can be written straight away, { (1,1,1,2), (1,2,-3,1), (3,4,-1,5) } (which is also the basis for the column space of the matrix), without verifying the vectors are linearly independent.. how come? The vectors in the matrix are not necessary linearly independent..
 
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Those three vectors cannot be a basis of anything, because they are linearly dependent. You can choose any three other columns to get an independent set.
 
mfb said:
Those three vectors cannot be a basis of anything, because they are linearly dependent. You can choose any three other columns to get an independent set.
Oh right.. I know how to do already, thanks!
 

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