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Catchfire
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Homework Statement
[itex]
A = \left( \begin{array}{ccc}
2 & 0 & -1 \\
4 & 1 & -4 \\
2 & 0 & -1 \end{array} \right)
[/itex]
Find the eigenvalues and corresponding eigenvectors that form a basis over R3
Homework Equations
The Attempt at a Solution
OK so I've found the characteristic polynomial: -λ(λ-1)2
so I know my eigenvalues are 0,1,1
Then to find the eigenvectors I sub the eigenvalues into the matrix A - λI
[itex]
A - 0I = \left( \begin{array}{ccc}
2 & 0 & -1 \\
4 & 1 & -4 \\
2 & 0 & -1 \end{array} \right)
[/itex]
then I solve:
2x -z = 0
4x + y -4z = 0
z = 2x
y = 4x
so my eigenvector is (1,4,2)
[itex]
A - 1I = \left( \begin{array}{ccc}
1 & 0 & -1 \\
4 & 0 & -4 \\
2 & 0 & -2 \end{array} \right)
[/itex]
x = z
so the eigenvector is (1,0,1)
Now I'm out of new eigenvalues to substitute. How do I find the last eigenvector?