Finding a closed form of the following

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SUMMARY

The discussion focuses on deriving a closed form for the recurrence relation ƒn = 14ƒn−1 − 32ƒn−2 + 24ƒn−3, which is a third-order linear homogeneous recurrence relation. The initial conditions provided are ƒ(0) = 2, ƒ(1) = 5, and ƒ(2) = 11. Participants suggest using characteristic equations and generating functions as potential methods to solve the recurrence. The conversation emphasizes the importance of understanding the roots of the characteristic polynomial to find the closed form.

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Homework Statement



Create a closed form for:
ƒn = 14ƒn − 1 − 32ƒn − 2 + 24ƒn − 3

Homework Equations



Initial conditions:
ƒ(0) = 2
ƒ(1) = 5
ƒ(2) = 11

The Attempt at a Solution



Because it's 3rd order, it has me confused as how to start it. I was thinking something along the lines of C1n, C2n-1 like you would for say, the Fibonacci Sequence, but I'm not entirely sure. What are the first few steps in solving this and the method involved?
 
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What techniques do you have available? Do you know about generating functions?
 

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