Finding a common divisor T that satisfies a condition

[mtayab1994]

Homework Statement

Look at my work in the picture.

Homework Equations

The Attempt at a Solution

I did a different method and I got 3 and 1 and still 1 is the only T that satisfies.

 

[Mark44]

Homework Statement

Look at my work in the picture.

Homework Equations

The Attempt at a Solution

View attachment 46620


I did a different method and I got 3 and 1 and still 1 is the only T that satisfies.

Your photo is very difficult to read. Also, what is the statement you are trying to prove?

 

[mtayab1994]

I'm trying to find all values of natural numbers T that satisfy T l n^2-n+3 and T l n+1

 

[mtayab1994]

Take a look at this copy and the bottom is cut off. It is S={1}

 

[Mark44]

If n = 4, n + 1 = 5 and n^2 -n + 3 = 15, so 5 is in the set.

 

[mtayab1994]

If n = 4, n + 1 = 5 and n^2 -n + 3 = 15, so 5 is in the set.

Yes, but it's not true for EVERY n in N. Aren't I correct?

Notice that I said "If n = 4".

Here's your problem statement from post #3.

I'm trying to find all values of natural numbers T that satisfy T l n^2-n+3 and T l n+1

There's no mention of "for every n."

 

[mtayab1994]

If n = 4, n + 1 = 5 and n^2 -n + 3 = 15, so 5 is in the set.

Yes it divides it but not for every n.