Finding a cubic polynomial that attains a max/min value over an open interval

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To find a cubic polynomial that attains both maximum and minimum values over the open interval (-1, 4), it is essential to ensure that the polynomial has distinct local extrema within this range. The derivative of the cubic function should equal zero at these extrema, indicating potential maximum and minimum points. One approach is to define the cubic polynomial in factored form as y = (x - a)(x - b)(x - c), ensuring that the x-intercepts (a, b, c) are positioned within the interval. By adjusting the coefficients or shifting and rescaling the function, the desired maximum and minimum can be achieved. Ultimately, a cubic polynomial can be constructed to meet these criteria effectively.
phosgene
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Homework Statement



Give an example of a cubic polynomial, defined on the open interval (-1,4), which reaches both its maximum and minimum values.

Homework Equations



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The Attempt at a Solution



I can see that I would need a function such that there is some f(a) and f(b) in (f(-1),f(4)) such that f(a) >= all f(x) for x in (-1,4) and f(b) <= all f(x) for x in (-1,4). I used an online tool to adjust the coefficients of a cubic until I got what I needed. But I have no idea how to do this by myself. All that I can think of is to somehow use the fact that at extrema, a function's derivative is zero.
 
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phosgene said:

Homework Statement



Give an example of a cubic polynomial, defined on the open interval (-1,4), which reaches both its maximum and minimum values.

Homework Equations



-

The Attempt at a Solution



I can see that I would need a function such that there is some f(a) and f(b) in (f(-1),f(4)) such that f(a) >= all f(x) for x in (-1,4) and f(b) <= all f(x) for x in (-1,4). I used an online tool to adjust the coefficients of a cubic until I got what I needed. But I have no idea how to do this by myself. All that I can think of is to somehow use the fact that at extrema, a function's derivative is zero.

Write your cubic as y = (x - a)(x - b)(x - c). The x-intercepts are at (a, 0), (b, 0), and (c, 0). Without too much effort you can put in values for a, b, and c so that all three intercepts are in the interval (-1, 4), with a local maximum between a and b, and a local minimum between b and c.
 
phosgene said:

Homework Statement



Give an example of a cubic polynomial, defined on the open interval (-1,4), which reaches both its maximum and minimum values.

Homework Equations



-

The Attempt at a Solution



I can see that I would need a function such that there is some f(a) and f(b) in (f(-1),f(4)) such that f(a) >= all f(x) for x in (-1,4) and f(b) <= all f(x) for x in (-1,4). I used an online tool to adjust the coefficients of a cubic until I got what I needed. But I have no idea how to do this by myself. All that I can think of is to somehow use the fact that at extrema, a function's derivative is zero.

You could find just any old cubic p(x) that has distinct maxima and minima, then shift and re-scale x until the max and min lie in your interval.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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