MHB Finding a formula for the multiplication of multiple formal power series

cbarker1
Gold Member
MHB
Messages
345
Reaction score
23
Dear Everyone,

I am having trouble with finding a formula of the multiplication 3 formula power series.
\[ \left(\sum_{n=0}^{\infty} a_nx^n \right)\left(\sum_{k=0}^{\infty} b_kx^k \right)\left(\sum_{m=0}^{\infty} c_mx^m \right) \]

Work:

For the constant term:
$a_0b_0c_0$

For The linear term : $(a_1 b_0 c_0 + a_0 b_1 c_0 + a_0 b_0 c_1)x$ + $a_0b_0c_0$

For the quadratic term: $a_2 b_2 c_2 x^6 + a_2 b_2 c_1 x^5 + a_2 b_1 c_2 x^5 + a_1 b_2 c_2 x^5 + a_2 b_2 c_0 x^4 + a_2 b_1 c_1 x^4 + a_1 b_2 c_1 x^4 + a_2 b_0 c_2 x^4 + a_1 b_1 c_2 x^4 + a_0 b_2 c_2 x^4 + a_2 b_1 c_0 x^3 + a_1 b_2 c_0 x^3 + a_2 b_0 c_1 x^3 + a_1 b_1 c_1 x^3 + a_0 b_2 c_1 x^3 + a_1 b_0 c_2 x^3 + a_0 b_1 c_2 x^3 + a_2 b_0 c_0 x^2 + a_1 b_1 c_0 x^2 + a_0 b_2 c_0 x^2 + a_1 b_0 c_1 x^2 + a_0 b_1 c_1 x^2 + a_0 b_0 c_2 x^2 + a_1 b_0 c_0 x + a_0 b_1 c_0 x + a_0 b_0 c_1 x + a_0 b_0 c_0$

I am seeing that the indexes are summing up to the power of x. But how to say that in the indexes?

Thanks,
Cbarker1
 
Physics news on Phys.org
Say we want to work with the terms [mat]a_2 x^2, ~ b_5 x^5, ~ c_3 x^2[/math]. The product of these terms is [math]a_2 b_5 c_3 x^{10}[/math]. If we have a more general term [math]a_i x^i b_j x^j c_k x^k = a_i b_j c_k x^{i + j + k}[/math] you can see the pattern. i + j + k is the power of x involved. Since all we need is the sum we get coefficients [math]a_i b_j c_k, ~ a_j b_k c_i, \text{ etc.}[/math], and we also get any other set of indicies were i + j + k are all the same number, the power of x.

For example, say we want the coefficient of the quartic term of x: [math]a_1 b_1 c_2 + a_1 b_2 c_1 + a_2 b_1 c_1[/math]

Or for the 6th power [math]a_1 b_1 c_4 + a_1 b_2 c_3 + a_1 b_3 c_2 + \text{ ...}[/math].

Does that help? Or am I misinterpreting your question?

-Dan
 
topsquark said:
Say we want to work with the terms [mat]a_2 x^2, ~ b_5 x^5, ~ c_3 x^2[/math]. The product of these terms is [math]a_2 b_5 c_3 x^{10}[/math]. If we have a more general term [math]a_i x^i b_j x^j c_k x^k = a_i b_j c_k x^{i + j + k}[/math] you can see the pattern. i + j + k is the power of x involved. Since all we need is the sum we get coefficients [math]a_i b_j c_k, ~ a_j b_k c_i, \text{ etc.}[/math], and we also get any other set of indicies were i + j + k are all the same number, the power of x.

For example, say we want the coefficient of the quartic term of x: [math]a_1 b_1 c_2 + a_1 b_2 c_1 + a_2 b_1 c_1[/math]

Or for the 6th power [math]a_1 b_1 c_4 + a_1 b_2 c_3 + a_1 b_3 c_2 + \text{ ...}[/math].

Does that help? Or am I misinterpreting your question?

-Dan

I think you misinterpreted my question. For instance, if I have $A$ and $B$ where $A=\sum_{n=0}^{\infty} a_nx^n$ and $B=\sum_{k=0}^{\infty} b_kx^k$, then $$AB=\sum_{n=0}^{\infty}\left(\sum_{k=0}^{n} a_nb_{k-n} \right)x^n$$. How can I do the index for the sum with power series?
 
From my previous post: How can I do the indices for the sum with 3 power series through the product? I am still confuse by how 3 would work based on the product of 2 power series...
 
Cbarker1 said:
For instance, if I have $A$ and $B$ where $A=\sum_{n=0}^{\infty} a_nx^n$ and $B=\sum_{k=0}^{\infty} b_kx^k$, then $$AB=\sum_{n=0}^{\infty}\left(\sum_{k=0}^{n} a_{\color{red}k}b_{\color{red}n-k} \right)x^n.$$ How can I do the index for the sum with power series?
Notice that you have got the indices wrong. For the coefficient of $x^n$ you want the subscripts on $a$ and $b$ to add up to $n$.[/color]

Along the same lines, $$ABC=\sum_{n=0}^{\infty}\left(\sum_{k=0}^{n}\left(\sum_{j=0}^{n-k} a_kb_{j}c_{n-k-j} \right)\right)x^n.$$
 
Back
Top