Finding a Hyperbola w/ 2 given points

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To find the equation of a hyperbola centered at the origin using the points (-10, 3π/2) and (2, π/2), it's important to first convert the polar coordinates to rectangular coordinates, which yield (0, 10) and (0, 2). The discussion reveals that a hyperbola centered at the origin cannot pass through both points in rectangular form, suggesting a fundamental issue with the problem setup. The equations for hyperbolas, either in the standard form or polar form, are not applicable here due to the conflicting coordinates. Thus, the problem may need reevaluation or clarification regarding the points provided.
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Homework Statement



Find the equation for a hyperbola centered at the origin with points (-10,3pi/2) and (2,pi/2)

Homework Equations



x^2/a^2 -y^2/b^2=1 or y^2/a^2 - x^2/b^2 = 1

* r=ke/(1±ecos(theta))

*cos can be replaced with sin and the ± is either a plus or a minus depending on the directrix

The Attempt at a Solution



I think the second equation is the only one that can be used but I do not know how to solve with that equation without guessing and checking.

Using the first equation I attempted to plug in values for x and y (they did not check out) in the first equation but I am pretty sure that the coordinates are polar coordinates. I am not really sure what to do but if you could point me in the right direction that would be great. Sorry I do not have the original problem so I do not know the question word for word. Any help would be much appreciated.
 
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yopoe said:

Homework Statement



Find the equation for a hyperbola centered at the origin with points (-10,3pi/2) and (2,pi/2)
...

I am pretty sure that the coordinates are polar coordinates.

If those are polar coordinates then they correspond to (0,10) and (0,2) in rectangular coordinates. No hyperbola centered at the origin could pass through both. (Assuming it isn't rotated, and maybe not even then.)
 
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