Finding a max angular acceleration

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SUMMARY

The discussion focuses on calculating the maximum angular velocity and corresponding angular acceleration of a 6-foot long, 40-pound bar pivoted at one end and released from a horizontal position to a 30-degree angle. The key equations involved include the sum of torques about the pivot point O, represented as Στ = I(α), and the relationship between angular acceleration and angular velocity given by a(t) = r*α. Participants emphasize the importance of using the moment of inertia of the bar about its end and the net torque as the rate of change of angular momentum to solve the problem.

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  • Familiarity with the moment of inertia for rigid bodies
  • Knowledge of angular velocity and angular acceleration concepts
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jhayes25
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Given is a 6' long 40 lb bar hung horizontally by a pin O at its end. It is released from its horizontal position and hits a stopper after reaching a 30 degree angle with the horizontal position at which it started. I am asked to find the value x for which the angular velocity is a maximum and also the corresponding angular acceleration alpha


Sum of the torques about O=I(alpha)
a(t)=r*alpha


I honestly do not know where to start with this one. do I start by summing moments about O?
Thanks in advance for any help.
 
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jhayes25 said:
Given is a 6' long 40 lb bar hung horizontally by a pin O at its end. It is released from its horizontal position and hits a stopper after reaching a 30 degree angle with the horizontal position at which it started. I am asked to find the value x for which the angular velocity is a maximum and also the corresponding angular acceleration alpha

Hi jhayes25! :smile:

(what's x? :confused:)

Hint: use the moment of inertia of the bar about its end, and net torque = rate of change of angular momentum. :wink:
 

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