Finding a power series representation

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SUMMARY

The discussion focuses on deriving a power series representation for the function f(x) = ln(5 + x^2) using the known power series for 1/(1-x). The key steps involve substituting q = -(x^2 + 4) into the geometric series formula and recognizing the relationship between the derivative of the logarithm and the geometric series. The final approach involves manipulating the function to fit the geometric series format and integrating term by term to obtain the logarithmic function. The radius of convergence is determined by the condition |q| < 1.

PREREQUISITES
  • Understanding of power series and their convergence
  • Familiarity with logarithmic functions and their derivatives
  • Knowledge of geometric series and their summation
  • Basic integration techniques for series
NEXT STEPS
  • Study the derivation of power series for common functions, particularly logarithmic functions
  • Learn about the radius of convergence for power series and how to calculate it
  • Explore the integration of power series term by term
  • Investigate the relationship between derivatives and power series representations
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Mathematics students, educators, and anyone interested in series expansions and their applications in calculus and analysis.

superdave
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Homework Statement



Start with the power series representation 1/(1-x) = sum from n=0 to inf. of x^n for abs(x) < 1 to find a power series representation for f(x) and determine the radius of convergence.

f(x)=ln(5+x^2)

Homework Equations






The Attempt at a Solution



Okay, so I get

1/(1-q)= sum q^n

Now, the problem lies in the fact that x is to a power of 2.

so if q= (-(x^2)-4) I get 1 / (1-(-(x^2)-4)) but if I want to integrate that, now that x is squared, I don't get the ln.

Can I do it the other way?

integrate first to get:

ln (1-q) = sum q^(n+1) / (n+1) and then replace q? I feel like that shouldn't work.
 
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My thoughts: f'(x) = 2x/(5 + x^2), right? So, keeping in mind that x is a constant term with respect to summation and all the work you've done, how would you write that as an infinite series?

Of course, I haven't done this in a while, so I could be completely wrong. Heh.
 
Yes. The derivative of ln(5+ x2 is 2x/(5+ x2). Now, you want to make that look like the sum of a geometric series a/(1- r). First, divide both numerator and denominator by 5: (2/5)x/(1+ x^2/5)= (2/5)x/(1- (-x^2/5)). Do see what a and r must be? Once you have the geometric series, integrate term by term to go back to the logarithm.
 

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