Finding a Second Linearly Independent Solution Using Reduction of Order

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Homework Help Overview

The discussion revolves around finding a second linearly independent solution to a differential equation using the method of reduction of order. The original poster presents a specific solution, y1 = x^(-1/2)cos(x), and seeks to determine another solution for the equation x^2y'' + xy' + (x^2 - 1/4) = 0.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the transformation of the differential equation into standard form and the application of Abel's method. There are questions about the correctness of the proposed solution and its satisfaction of the original equation. Some suggest verifying the solution by substituting it back into the differential equation.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the problem and the validity of the original solution. There is a suggestion to check the correctness of the differential equation and the proposed solution, indicating a productive direction in the inquiry.

Contextual Notes

There are indications that the original solution provided may not satisfy the given differential equation, prompting participants to question the accuracy of the problem statement and the solution itself.

Mark Brewer
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Homework Statement


(Reduction of order) The function y1 = x-1/2cosx is one solution to the differential equation x2y" + xy' + (x2 - 1/4) = 0. Use the method of reduction of order to find another linearly independent solution.

The Attempt at a Solution



I divided x2 to both sides to get the equation into y" + py' + qy = 0

y" + (1/x)y' + ((1 - (1/4x2)) = 0

Using Abel's method

c e-∫(p)dx

= c e-ln x
y2 = -c lnx[/B]

Am I doing this right?
 
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Mark Brewer said:

Homework Statement


(Reduction of order) The function y1 = x-1/2cosx is one solution to the differential equation x2y" + xy' + (x2 - 1/4) = 0. Use the method of reduction of order to find another linearly independent solution.

The Attempt at a Solution



I divided x2 to both sides to get the equation into y" + py' + qy = 0

y" + (1/x)y' + ((1 - (1/4x2)) = 0

Using Abel's method

c e-∫(p)dx

= c e-ln x
y2 = -c lnx[/B]

Am I doing this right?
Take y2 and plug it back into the original differential equation and see if it is satisfied. :wink:
 
Mark Brewer said:

Homework Statement


(Reduction of order) The function y1 = x-1/2cosx is one solution to the differential equation x2y" + xy' + (x2 - 1/4) = 0. Use the method of reduction of order to find another linearly independent solution.

The Attempt at a Solution



I divided x2 to both sides to get the equation into y" + py' + qy = 0

y" + (1/x)y' + ((1 - (1/4x2)) = 0

Using Abel's method

c e-∫(p)dx

= c e-ln x
y2 = -c lnx[/B]

Am I doing this right?
No, the problem said to use the method of reduction of order.

But first, did you type the differential equation and solution correctly? I ask because the supposed solution doesn't satisfy the given differential equation.
 
Mark Brewer said:

Homework Statement


(Reduction of order) The function y1 = x-1/2cosx is one solution to the differential equation x2y" + xy' + (x2 - 1/4) = 0.
You mean x2y" + xy' + (x2 - 1/4)y = 0, don't you? As Vela pointed out, the given y1 does not satisfy the equation you gave. Perhaps it satisfies this one. I haven't checked.

Use the method of reduction of order to find another linearly independent solution.
So you start by looking for a solution of the form y_2= u(x)x^{1/2}cos(x)
Find the first and second derivatives of that and put them into the equation. If your given function really is a solution to the differential equation, then all terms involving only "u" (as opposed to u' or u'') will cancel leaving a first order equation for v= u'.

3. The Attempt at a Solution

I divided x2 to both sides to get the equation into y" + py' + qy = 0

y" + (1/x)y' + ((1 - (1/4x2)) = 0

Using Abel's method

c e-∫(p)dx

= c e-ln x
y2 = -c lnx
Am I doing this right?
Mark Brewer said:

Homework Statement


(Reduction of order) The function y1 = x-1/2cosx is one solution to the differential equation x2y" + xy' + (x2 - 1/4) = 0. Use the method of reduction of order to find another linearly independent solution.

The Attempt at a Solution



I divided x2 to both sides to get the equation into y" + py' + qy = 0

y" + (1/x)y' + ((1 - (1/4x2)) = 0

Using Abel's method

c e-∫(p)dx

= c e-ln x
y2 = -c lnx[/B]

Am I doing this right?
 

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