Finding a Slope of Any Linear Function Without Using (x2-x1; y2-y1)

In summary, a linear function can be written as y = ax + b and the slope of the tangent line at any point on the curve can be found by evaluating the derivative of the function at that point.
  • #1
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Hi everyone,

Please I have a problem to find a slope (Tangent line) of any linear function without using (x2-x1; y2-y1).
What I want is a function that can be applied in any position of any type of function, example: x2, 3x3+sin(x), ln(x)+x3, and so one. (Like as in this web page "Java Applet" : http://www.math.brown.edu/help/tangentline.html [Broken])

Thank you.
 
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  • #2
naoufelabs said:
Hi everyone,

Please I have a problem to find a slope (Tangent line) of any linear function without using (x2-x1; y2-y1).
What I want is a function that can be applied in any position of any type of function, example: x2, 3x3+sin(x), ln(x)+x3, and so one. (Like as in this web page "Java Applet" : http://www.math.brown.edu/help/tangentline.html [Broken])

Thank you.

Is this a homework problem?

What you are asking is unclear. A linear function is one with the form f(x) = ax + b. This function's graph is a straight line with slope a.

For other functions, such as the ones you mentioned, the slope of the tangent line at a point on the curve, is given by the derivative of the function, evaluated at the x value at the point in question.

So are you asking about linear functions or functions in general?
 
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  • #3
I ask about linear function.
 
  • #4
Any linear function of x can be written as y= ax+ b for some numbers a and b. The slope is the number a.
 
  • #5
Thanks
 

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