Finding a solution for Relativistic Acceleration

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Discussion Overview

The discussion revolves around finding a solution to a time-based differential equation related to relativistic acceleration, particularly in the context of Rindler coordinates. Participants explore various methods and substitutions for solving the equation, including both mathematical software and analytical techniques.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses difficulty in finding a solution using software like Maple and suggests that solving differential equations often involves guessing and checking.
  • Another participant proposes a solution involving a change of variables and provides a specific form of the solution in terms of hyperbolic functions.
  • A different participant emphasizes the importance of learning standard techniques for solving differential equations rather than relying solely on software, suggesting a separation of variables approach and a trigonometric substitution.
  • Further discussion includes alternative substitutions for the integral, with one participant noting that both sine and hyperbolic tangent substitutions lead to valid results.
  • One participant references the Gudermannian transformation, linking it to the substitutions discussed and suggesting further reading on the topic.

Areas of Agreement / Disagreement

Participants present multiple approaches to solving the differential equation, with no consensus on a single method or solution. There is a mix of agreement on the validity of different techniques, but also a lack of resolution regarding the best approach.

Contextual Notes

The discussion includes various assumptions about the parameters and the forms of the solutions, which may not be universally applicable. The reliance on specific substitutions and transformations introduces additional complexity that remains unresolved.

Michio Cuckoo
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I tried all my mathcad software such as Maple and I can't seem to find a solution to this time based differential equation.

m}\left%20(%201%20-%20\frac{\left%20[%20f(t)%20\right%20]^{2}}{c^{2}}%20\right%20)^{\frac{3}{2}}.gif
 
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Michio Cuckoo said:
I tried all my mathcad software such as Maple and I can't seem to find a solution to this time based differential equation.

m}\left%20(%201%20-%20\frac{\left%20[%20f(t)%20\right%20]^{2}}{c^{2}}%20\right%20)^{\frac{3}{2}}.gif

Solving differential equations is often a matter of guessing and checking.
This equation comes up in Rindler coordinates, so I actually know the solution.

Let g = F/m.
Switch to a new independent variable T that is related to t through
t = c/g sinh(gT/c).

Then try the solution:

f = c tanh(gT/c)

In terms of the original t, we can rewrite f as

f = c (gt/c)/√(1 + (gt/c)2)

or

f = c (ct)/√((ct)2 + c2/g)
 
Solving differential equations is often a matter of guessing and checking.
Michio, It's important part of everyone's physics education to pick up some standard techniques for solving DEs, so you don't have to depend entirely on the math software to do it for you, which often does an imperfect job. And this equation is a very easy one to solve. Setting the constant parameters to one to simplify the discussion,

df/dt = (1 - f2)3/2

Separate the variables (t on one side, f on the other) and integrate immediately:

t = ∫(1 - f2)-3/2 df

To do the integral, the factor 1 - f2 suggests making a trig substitution. Let f = sin θ.

t = ∫(cos θ)-3 cos θ dθ = ∫ sec2 θ dθ = tan θ

So we have f = sin θ, t = tan θ, giving us an algebraic relationship and the solution:

t = f/√(1 - f2) or f = t/√(1 + t2)
 
Bill_K said:
t = ∫(1 - f2)-3/2 df

To do the integral, the factor 1 - f2 suggests making a trig substitution. Let f = sin θ.

Interestingly, it works to try the substitution f = sin(θ), then you get t = tan(θ), but it also works to try the substitution f = tanh(θ), then you get t = sinh(θ). I like the latter better, because that gets you to the Rindler coordinates.
 
sin θ = tanh χ
cos θ = sech χ
tan θ = sinh χ

is known as the Gudermannian transformation and written θ = gd χ. See "Gudermannian Function" in Wikipedia.
 

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