1. The problem statement, all variables and given/known data Suppose the water at the top of Niagara Falls has a horizontal speed of 1.42 m/s just before it cascades over the edge of the falls. At what vertical distance below the edge does the velocity vector of the water point downward at a 61.8 ° angle below the horizontal? 2. Relevant equations Not sure 3. The attempt at a solution Initial velocity(u) of Niagara falls = 1.42 m/s Angle(θ) at which it strikes the ground = 61.8o Formula used: tan(61.8) = sq.rt(2*9.8*x/1.42) I solved for x and got .252 m but the answer is wrong. Now I have no idea on what to do. Any help would be appreciated. Thank you.