Finding Acceleration Given Coordinates

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SUMMARY

The discussion focuses on calculating the acceleration of an object moving with uniform acceleration, given its initial velocity of 11.0 cm/s and a displacement from 2.91 cm to -5.00 cm over a time interval of 2.75 seconds. The calculated acceleration is -10.1 cm/s². Participants suggest using the SUVAT equations of motion, specifically the relationship between displacement, time, initial velocity, and acceleration to derive the solution.

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No idea how to do this.

An object moving with uniform acceleration has a velocity of 11.0 cm/s in the positive x-direction when its x-coordinate is 2.91 cm. If its x-coordinate 2.75 s later is −5.00 cm, what is its acceleration?

The answer is -10.1 cm/s squared but I don't know how to get to the answer. Any help would be great. Thanks.
 
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As you know velocity=Δdisplacement/Δtime.
What do you know about constant acceleration definition?
 
Perhaps look at one of the SUVAT equation of motion.

You know the displacement s, the time t and the initial velocity v.

I'll let you decide which equation you need to solve for "a".
 

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